Make sure you are confident in solving one and two-step linear equations and expanding brackets in order to tackle these more complex types of equations. Substitute close substituteIn algebra, to ...
\(y = x + 3\) is a linear equation and \(y = x^2 + 3x\) is a quadratic equation. If the product of two numbers is zero, then one or both numbers must also be equal to zero. To solve, put each bracket ...
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